Nuprl Lemma : fpf-sub_functionality 11,40

AA':Type.
strong-subtype(A;A')
 (B:(AType), C:(A'Type), eq:EqDecider(A), eq':EqDecider(A'), fg:a:A fp B(a).
 (a:AB(aC(a))  {f  g  f  g}) 
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Definitions{T}
Lemmasfpf-sub-functionality

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